100x^2-5x-5=0

Solution for 100x^2-5x-5=0 equation:

100x^2-5x-5=0

a = 100; b = -5; c = -5;
Δ = b2-4ac
Δ = -52-4·100·(-5)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-45}{2*100}=\frac{-40}{200}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+45}{2*100}=\frac{50}{200}
=1/4
$